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If 6.3 g of NaHCO(3) are added to 15.0 g...

If 6.3 g of `NaHCO_(3)` are added to 15.0 g of `CH_(3)COOH` solution, the residue is found to weigh 18.0 g. The mass of `CO_(2)` released in the reaction is

A

9.3 g

B

39.3 g

C

3.3 g

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
`CH_(3)COOH+NaHCO_(3) to CH_(3)COONa+H_(2)O+CO_(2) uarr`
Mass of reactants = Mass of products
`6.3 g + 15.0 g= 18.0 g+` Mass of `CO_(2)`
Mass of `CO_(2) = 6.3g + 15.0g - 18.0 g = 3.3 g`
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