If Avogadro's number would have been `1xx10^(23) mol^(-1)`, then mass of one atom of `._(8)O^(16)` would have been

Options

A. 16 amu
B. `(16)/(6.02)amu`
C. `(16xx6.02)amu`
D. `16xx10^(-23)` amu

Answer

B

Explanation

On new scale
1 a.m.u `= (1)/(12)xx(12g)/(1xx10^(23))g`
Mass of 1 atom of `._(8)O^(16) = (16)/(6.02xx10^(23))g`
`(16xx10^(-23))/(6.02)g`
`=((16xx10^(-23)g)/(6.02))xx((1 a.m.u)/(10^(-23)g)) = (16)/(6.02)` a.m.u.