A compound has hemoglobin-like structure. It has one `Fe` and contains `4.6%` of `Fe`. The approximate molecular mass is

Options

A. `100 g mol^(-1)`
B. `1200 g mol^(-1)`
C. `1600 g mol^(-1)`
D. `1400 g mol^(-1)`

Answer

B

Explanation

If 4.6 of Fe is present mass of compound = 100 g
If 56 a.m.u. of Fe is present mass of compound
`= (100)/(46)xx56 a.m.u.`
`1217.39 a.m.u.`
Molar mass of compound `= 1217.39 g mol^(-1)`