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What is the total number of atoms presen...

What is the total number of atoms present in 25.0 mg of camphor, `C_(10)H_(16)O`?

A

`9.89xx10^(19)`

B

`6.02xx10^(20)`

C

`9.89xx10^(20)`

D

`2.67xx10^(21)`

Text Solution

Verified by Experts

The correct Answer is:
D
Molar mass of `C_(10)H_(16)O = 12+16+16 = 152 g mol^(-1)`
`25.0 mg = 25.0 mgxx((1)/(10^(3)mg))xx((1mol)/(152g))xx(27xx6.02xx10^(23)atoms)/(1mol)`
`=(25xx27xx6.02)/(152)xx10^(20)` atom
`= 26.73xx10^(20)` atom `= 2.67xx10^(21)` atoms
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