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Volume of a gas at S.T.P. is 1.2xx10^(-7...

Volume of a gas at S.T.P. is `1.2xx10^(-7)` cc. Calculate the no. of molecules in it

A

`3.01xx10^(20)`

B

`3.01xx10^(12)`

C

`3.01xx10^(23)`

D

`3.01xx10^(24)`

Text Solution

Verified by Experts

The correct Answer is:
B
No. of molecules = `(1.12xx10^(-7))/(22,400) = (10^(-9))/(200)`
`= 0.5xx10^(-11)` moles
`= 0.5xx10^(-11)xx6.02xx10^(23)`
`3.01xxx10^(12)`molecules
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