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An organic compound contains 49.3% carbo...

An organic compound contains 49.3% carbon. 6.84% hydrogen and its vapour density is 73. Molecular formula of compound is

A

`C_(3)H_(5)O_(2)`

B

`C_(6)H_(10)O_(4)`

C

`C_(3)H_(10)O_(2)`

D

`C_(4)H_(10)O_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`:. E.F. = C_(3)H_(5)O_(2)`
E.F. mass `= 12xx3+5xx1+16xx2 = 73`
Mol. Mass `= 2xxV.D. = 2xx73 = 146`
`:. n = ("Mol mass")/("E.F. mass") = (146)/(73) = 2`
`:.` Molecular formula `= (E.F.)_(n) = (C_(3)H_(5)O_(2))_(2)`
`= C_(6)H_(10)O_(4)`
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