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0.126 g of acid required 20 mL of 0.1 N ...

0.126 g of acid required 20 mL of 0.1 N NaOH for complete neutralisation. The equivalent mass of an acid is

A

`45`

B

`53`

C

`40`

D

`63`

Text Solution

Verified by Experts

The correct Answer is:
D
Let equivalent mass be E
`:.` g-equivalent of acid `= (0.126)/(E)`
G-equivalents of acid = G equi. Of base
or `(0.126)/(E) = 20xx10^(-3)xx0.1`
or `E = (0.126xx10^(3))/(20xx0.1)=63`
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