Number of atoms in `558.5` ` g ` `Fe (at.wt.55.85)` is:

Options

A. twice that in 60g carbon
B. `6.022xx10^(2)`
C. half that in 8 g of He
D. `558.5xx6.022xx10^(23)`

Answer

A

Explanation

No. of atoms in 55.85g of Fe `= 6.02xx10^(23)`
`:.` No. of atoms in 558.5 of Fe `= 6.02xx10^(24)`
No. of atoms in 12 g of C-12 `= 6.02xx10^(23)`
`:.` No. of atoms in 60 g of C-12
`= 5xx6.02xx10^(23)`
`= 30.1xx10^(23)`
`("No. of atoms in 558.8 g of Fe")/("No. of atoms in 60 g of C-12") = (6.02xx10^(24))/(30.1xx10^(23))=2`
No. of atoms in 60g of C-12 = 12
`:.` No. of atoms in 558.5 g of Fe
`=2xx"No. of atoms in 60 g of C-12"`