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0.56 g of a gas occupies 280 cm^(3) at N...

0.56 g of a gas occupies `280 cm^(3)` at N.T.P., then its molecular mass is

A

`4.8`

B

`44.8`

C

`2`

D

`22.4`

Text Solution

Verified by Experts

The correct Answer is:
B
`280 cm^(3)` of the gas at N.T.P. has mass = 0.56g
`:. 22400 cm^(3)` of the gas at N.T.P. has mass
`= (0.56g)/(280cm^(3))xx22400cm^(3)`
`= 44.8 g`
`:.` Molecular mass of the gas = 44.8
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