Two grams sulphur is completely burnt in oxygen to form `SO_(2)`. In this reaction, what is the volume (in litres) of oxygen consumed at S.T.P. ?(at mass of S and O are 32 and 16 respectively)

Options

A. `(16)/(22.414)`
B. `(22.414)/(16)`
C. `(22.414)/(32)`
D. `(32)/(22.414)`

Answer

B

Explanation

`underset(32g)(S)+underset(22.414L)(O_(2))toSO_(2)`
32 g S required `O_(2)` at S.T.P. = 22414 L
2 g of S require `O_(2)` at S.T.P. `= (22.414)/(32)xxL`
`=(22.414)/(16)L`