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Mg+2HCl toMgCl(2)+H(2). The ration of Mg...

`Mg+2HCl toMgCl_(2)+H_(2)`. The ration of Mg used to `H_(2)` produced by weight is

A

`1:12`

B

`12:1`

C

`24:1`

D

`1:6`

Text Solution

Verified by Experts

The correct Answer is:
B
`underset(24g)(Mg)+2HCl to MgCl_(2)+underset(2g)(H_(2))`
Mass of Mg used: Mass of hydrogen produced
`= 24:2=12:1`
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