A metal M of equivalent mass E forms an oxide of molecular formula `M_(x)O_(y)`. The atomic mass of the metal is given by the correct equation.

Options

A. 2E(y/x)
B. xy/E
C. E/y
D. E/2(x/y)

Answer

A

Explanation

If m is the atomic mass of the metal M, then 16y g of oxygen combine with xm g of the metal
`:.` 8 g of oxygen will combine with metal
`= (xm)/(16y)xx8 = (xm)/(2y)`
`:. (xm)/(2y)=E`
or `m=2E//(y//x)`