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Empirical formula of a compound is CH(2)...

Empirical formula of a compound is `CH_(2)O` and its molecular mass is 90. The molecular formula of the compound is

A

`C_(2)H_(4)O_(2)`

B

`C_(3)H_(6)O_(3)`

C

`C_(4)H_(8)O_(4)`

D

`CH_(2)O`

Text Solution

Verified by Experts

The correct Answer is:
C
E.F. mass `= 12+2xx1+16=30`
Mol. Mass = 120
`n = ("Mol. Mass")/("E.F. mass")=(120)/(3)=4`
`:.` Mol formula `= (CH_(2)O)_(4) = C_(4)H_(8)O_(4)`
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