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2g of aluminium is treated, separately w...

2g of aluminium is treated, separately with excess of dilute `H_(2)SO_(4)`, and excess of `NaOH`, the ratio of volumes of hydrogen evolved is

A

`1:1`

B

`2:3`

C

`1:2`

D

`2:1`

Text Solution

Verified by Experts

The correct Answer is:
A
`2Al + 3H_(2)SO_(4)toAl_(2)(SO_(4))_(3)+3H_(2)`
`2Al+2NaOH+6H_(2)Oto2Na[Al(OH)_(4)]+3H_(2)`
In both the equations equal mass of aluminium produces equal volumes of `H_(2)`
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