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Number of atoms of oxygen present in 10....

Number of atoms of oxygen present in 10.6 g of `Na_(2)CO_(3)` will be

A

`6.02xx10^(22)`

B

`12.04xx10^(22)`

C

`1.806xx10^(23)`

D

`31.80xx10^(28)`

Text Solution

Verified by Experts

The correct Answer is:
C

Molar mass of `Na_(2)CO_(3) = 2xx23+1216xx3`
`=46+12+48`
`=106gmol^(-1)`
`:.` 10.6 g of `Na_(2)CO_(3)-=0.1` mol of `Na_(2)CO_(3)`
`=0.3` mol of oxygen atoms
`=0.3xx6.02xx10^(-23)` oxygen atom
`=1.806xx10^(23)` oxygen atom
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