10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be

Options

A. `3mol`
B. `4mol`
C. `1mol`
D. `2mol`

Answer

B

Explanation

`10g H_(2) = (10)/(2)=5` mol,
64 g of `O_(2) = (64)/(32) = 2` mol
`{:(H_(2),+,(1)/(2)O_(2),to,H_(2)O),(1mol,,0.5mol,,1mol),(5mol,,2.5mol,,5mol),(,,2mol,,?):}`
In 5 mol of oxygen needed = 2.5 mol which not present `:. O_(2)` is the limiting reactant. Hence `H_(2)O` formed from 2 mol is 4 mol.