How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl?

Options

A. `0.044`
B. `0.333`
C. `0.011`
D. `0.029`

Answer

D

Explanation

`PbO+2HCl toPbCl_(2)+H_(2)O`
Mol. Mass of PbO `= 207+16=223 g mol^(-1)`
`:. 6.5 g PbO =(6.5)/(223)` mole `=0.029` mole
Molecular mass of HCl `=(3.2)/(36.5)` mole
`=0.0877` mole
1 mole of PbO reacts with 2 moles of HCl
Thus PbO is the emiting reactant
1 mole of PbO will produce `PbCl_(2) = 0.029` mole