For reaction `A+2BtoC`. The amount of C formed by starting the reaction with 5 mole of A and 8 mole of B is :

Options

A. 5 moles
B. 8 moles
C. 16 moles
D. 4 moles

Answer

D

Explanation

`A+2BtoC`
1 mole of A reacts with 10 moles of B
`:.` 5 moles of A will react with 10 moles of B
But we have only 8 moles of B, `:.` B is the limiting reagent
2 moles of B will form 1 mole of C
`:.` 8 moles of B will form C = 4 moles