Arrange the following in the order of increasing mass (at. Mass of O=16, Cu=63, N=14)
(I) one atom of oxygen (II) one atom of nitrogen
(III) `1xx10^(-10)` mole of oxygen (IV) `1xx10^(-10)` mole of copper

Options

A. II lt I lt III lt IV
B. I lt II lt III lt IV
C. III lt II lt IV lt I
D. IV lt II lt III lt I

Answer

A

Explanation

(i) 1 atom of oxygen `=(16)/(6.02xx10^(23)g)`
`=2.65xx10^(-23)g`
(ii) 1 atom of nitrogen `=(14)/(6.02xx10^(23))g`
`=2.326xx10^(-23)g`
(iii) `1xx10^(-10)` mol of oxygen `=32xx10^(-10)`
`=3.2xx10^(-9)`g
(iv) `1xx10^(-10)` mol of `CO=63.5xx10^(-10)g`
`=6.35xx10^(-9)`g
Thus, the increaseing order of mass is
II lt I lt III lt IV