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In acidic medium, equivalent weight of K...

In acidic medium, equivalent weight of `K_(2)Cr_(2)O_(7)` (molecular weight `= M`) is

A

`M//3`

B

`M//4`

C

`M//6`

D

`M//7`

Text Solution

Verified by Experts

The correct Answer is:
C
`overset(+6)(Cr_(2))+14H^(+)+6e^(-) to 2Cr^(+3)+7H_(2)O`
Reduction of `Cr_(2)O_(7)^(2-)` in acidic medium to `Cr^(3+)` requires six electrons
`:.` Equivalent of `K_(2)Cr_(2)O_(7)` in acidic medium
`=("Mol. Mass")/(6)`
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