If `10^(21)` molecules are removed from 200 mg of `CO_(2)`, then maximum number of moles of `Ba_(3)(PO_(4))_(2)` that can be formed is

Options

A. `2.88xx10^(-3)`
B. `1.66xx10^(-3)`
C. `4.54xx10^(-3)`
D. `1.66xx10^(-2)`

Answer

A

Explanation

`10^(21)` molecules of `CO_(2)`
`(10^(21))/(6.02xx10^(23))`moles
`=1.66xx10^(-3)` moles
200 mg of `CO_(2)` left `=(200xx10^(-3))/(44)`moles
`=4.54xx10^(-3)` moles
Moles of `CO_(2)` left `=(4.54-1.66)xx10^(-3)`
`=2.88xx10^(-3)` moles