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The answer to each of the following ques...

The answer to each of the following questions is a single digit integer, ranging from 0 to 9. If correct answers to the question number A,B,C and D (say) are 4,0,9 and 2 respectively, then correct darkening of bubbles should be as shown on the side.
(D) 29.2 (w/w) HCl stock solution has a density of 1.25 g `mL^(-1)`. The molecular weight of HCl is 36.5 g `mol^(-1)`. The volume (mL) of stock solution required to prepare a 200 mL solution of 0.4 M HCl is ..........................

Text Solution

Verified by Experts

The correct Answer is:
8
`M_(HCl)=36.5g mol^(-1), d = 1.25mL^(-1)`
weight-weight percentage of HCl = 29.3
Mass of HCl m 100 g solution = 29.2 g
Volume of solution `=(100g)/(1.25gmL^(-1))=80`
Molarity `=("Mass of solute")/("Mol. Mass")xx(1000)/("volume of solution")`
`=(29.2//36.5)/(80)xx1000=10M`
Using `M_(1)V_(1)=M_(2)V_(2)`
`10xxV_(1)=0.4xx200`
`V_(1)=(0.4xx200)/(10)=8mL`
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