IUPAC name of the `CH_(3)-CH(Br)-CH(CH_(3))+COOH` is

Options

A. 2-Bromo-3-methyl butanoic acid
B. 1-Bromo-3-methyl butanoic acid
C. 2-Bromo-3-methl butane
D. 3-Bromo-2-methyl butanoic acid

Explanation

To determine the IUPAC name of the compound `CH3-CH(Br)-CH(CH3)-COOH`, we will follow these steps:

### Step 1: Identify the Structure
The given formula can be broken down into its components:
- `CH3` (methyl group)
- `CH(Br)` (carbon with a bromine substituent)
- `CH(CH3)` (carbon with a methyl group)
- `COOH` (carboxylic acid functional group)

### Step 2: Draw the Structure
From the breakdown, we can draw the structure:
```
CH3
|
CH3-CH-COOH
|
Br
```

### Step 3: Determine the Longest Carbon Chain
Identify the longest continuous carbon chain that includes the carboxylic acid group:
- The longest chain here has 4 carbon atoms, which corresponds to butane.

### Step 4: Number the Carbon Chain
Number the carbon chain starting from the end closest to the carboxylic acid group (COOH):
1. COOH (C1)
2. CH (C2)
3. CH(Br) (C3)
4. CH3 (C4)

### Step 5: Identify Substituents
- At C2, there is a methyl group (CH3).
- At C3, there is a bromine atom (Br).

### Step 6: Assign Locants to Substituents
- The methyl group is on carbon 2.
- The bromine is on carbon 3.

### Step 7: Combine the Information
According to IUPAC nomenclature:
- The substituents are listed in alphabetical order.
- The name will include the base name derived from the longest chain (butane) and the functional group (carboxylic acid).

### Step 8: Write the Final IUPAC Name
Putting it all together, we have:
- 3-bromo (from bromine at C3)
- 2-methyl (from the methyl group at C2)
- Butanoic acid (from the 4-carbon chain with a carboxylic acid)

Thus, the IUPAC name is **3-bromo-2-methylbutanoic acid**.

### Summary of the IUPAC Name
The final IUPAC name of the compound is **3-bromo-2-methylbutanoic acid**.

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