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Consider the following alkenes : 1. H(...

Consider the following alkenes :
1. `H_(2)C=C(CH_(2)CH_(3))CH(CH_(3))_(2)`
2. `(CH_(3))_(2)C=C(CH_(3))CH_(2)CH_(3)`
3. `CH_(3)CH=C(CH_(3))CH(CH_(3))_(2)`
The correct sequence of increasing order of stability of these alkenes is :

A

1,2,3

B

3,2,1

C

2,1,3

D

1,3,2.

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The correct Answer is:
To determine the stability of the given alkenes, we will analyze the number of alpha-hydrogens present in each compound. The more alpha-hydrogens an alkene has, the more stable it is due to the hyperconjugation effect. ### Step 1: Identify the Structures of the Alkenes 1. **Alkene 1**: `H2C=C(CH2CH3)CH(CH3)2` 2. **Alkene 2**: `(CH3)2C=C(CH3)CH2CH3` 3. **Alkene 3**: `CH3CH=C(CH3)CH(CH3)2` ### Step 2: Count the Alpha-Hydrogens - **Alpha-hydrogens** are the hydrogens attached to the carbons adjacent to the double bond. #### For Alkene 1: - The structure is: `H2C=C(CH2CH3)CH(CH3)2` - The carbons adjacent to the double bond are: - CH2 (from CH2CH3) has 2 alpha-hydrogens. - CH (from CH(CH3)2) has 1 alpha-hydrogen. - Total alpha-hydrogens = 2 + 1 = **3 alpha-hydrogens**. #### For Alkene 2: - The structure is: `(CH3)2C=C(CH3)CH2CH3` - The carbons adjacent to the double bond are: - C (from (CH3)2) has 6 alpha-hydrogens (3 from each CH3). - CH2 (from CH2CH3) has 2 alpha-hydrogens. - Total alpha-hydrogens = 6 + 2 = **8 alpha-hydrogens**. #### For Alkene 3: - The structure is: `CH3CH=C(CH3)CH(CH3)2` - The carbons adjacent to the double bond are: - CH3 (from CH3) has 3 alpha-hydrogens. - CH (from C(CH3)CH(CH3)2) has 1 alpha-hydrogen. - CH (from CH(CH3)2) has 1 alpha-hydrogen. - Total alpha-hydrogens = 3 + 1 + 1 = **5 alpha-hydrogens**. ### Step 3: Determine the Stability Order Now, we can summarize the findings: - Alkene 1 has **3 alpha-hydrogens** (least stable). - Alkene 3 has **5 alpha-hydrogens** (moderately stable). - Alkene 2 has **8 alpha-hydrogens** (most stable). ### Conclusion The correct sequence of increasing order of stability of these alkenes is: **Alkene 1 < Alkene 3 < Alkene 2**. ### Final Answer 1. **Alkene 1** (least stable) 2. **Alkene 3** (moderately stable) 3. **Alkene 2** (most stable)

To determine the stability of the given alkenes, we will analyze the number of alpha-hydrogens present in each compound. The more alpha-hydrogens an alkene has, the more stable it is due to the hyperconjugation effect. ### Step 1: Identify the Structures of the Alkenes 1. **Alkene 1**: `H2C=C(CH2CH3)CH(CH3)2` 2. **Alkene 2**: `(CH3)2C=C(CH3)CH2CH3` 3. **Alkene 3**: `CH3CH=C(CH3)CH(CH3)2` ### Step 2: Count the Alpha-Hydrogens ...
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Consider the following carbocations I overset(+)underset((CH_(3))_(3)C CH_(2) II (CH_(3))_(3)C^(+) III {:(" " +),(CH_(3)CH_(2)CH_(2)):} IV {:(" " +),(CH_(3)-CH-CH_(3)):} The correct order for the stability of the above carbocations is

The IUPAC name of the following structure is [CH_(3)CH(CH_(3))]_(2)C(CH_(2)CH_(3))C(CH_(3))C(CH_(2)CH_(3))_(2)

The following two isomeric alkenes are related as - (I) CH_(3)-CH=CH-CH_(2)-CH_(2)-CH_(3) (II) CH_(3)-CH_(2)-CH=CH-CH_(2)-CH_(3)

IUPAC name of the following compound {:(H_(3)C-CH_(2)-CH-CH_(2)-CH-CH_(2)CH_(3)),(" |"" |"),(" "CH_(2)CH_(3)" "CH_(3)):} is

What is the order of the boiling points of following alkanes explain (I). CH_(3)-(CH_(2))_(4)-CH_3 (II). CH_(3)-CH_(2)-CH(CH_(3))-CH_(2)-CH_(3) (III). CH_(3)-C(CH_(3))_(2)-CH_(2)-CH_(3)

IUPAC name of the following are {:(" "CH_(3)),(" |"),(CH_(3)-N-C-CH_(2)-CH_(3)),(" |"" |"),(" "CH_(3)""C_(2)H_(5)):}

The correct IUPAC name of CH_(3)CH_(2)CH(CH_(3))CH(C_(2)H_(5))_(2) is

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