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The decreasing order of the stability of...

The decreasing order of the stability of the ions
`underset((I))underset()(CH_(3)-overset(+)CH-CH_(3)),` `underset((II))underset()(CH_(3)-overset(+)CH-OCH_(3)),` , `underset((III))underset()(CH_(3)-overset(+)CH-COCH_(3)),`

A

`IgtIIgtIII`

B

`IIIgtIIgtI`

C

`IIgtIIIgtI`

D

`IIgtIgtIII.`

Text Solution

Verified by Experts

The correct Answer is:
D

Carbocation (II) is most stable due to resonance

Carbocation Ill is least stable due to electron withdrawing nature of carbonyl group. Carbocation (I) is less stable than (II) because it is stabilised only by the + I effect of the two methyl groups.

Therefore correct order of decreasing stability is `IIgtIgtIII`
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What si the correct order of decreasing stability of the following carbocations. underset(I.)(CH_(3)-overset(o+)(C)H-CH_(3))" "underset(II.)(CH_(3)-overset(o+)(C)H-OCH_(3)) underset(III.)(CH_(3)-overset(o+)(C)H-CH_(2)-OCH_(3))

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Arrange the following free radicals in order of stability underset(I)underset()((CH_(3))_(3)overset(cdot)C)" "underset(II)underset()((CH_(3))_(2)overset(cdot)CH)" "underset(III)underset()(CH_(3)overset(cdot)CH_(2))" "underset(IV)underset()(overset(cdot)CH_(3))

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