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Formation of polyethylene from calcium c...

Formation of polyethylene from calcium carbide takes place as follows
`CaC_(2)+2 H_(2)O rarr Ca(OH)_(2)+C_(2)H_(2)`
`C_(2)H_(2)+H_(2) rarr C_(2)H_(2)`
`N(C_(2)H_(4)) rarr (-CH_(2)-CH_(2)-)_(n)`
The amount of polyethylene obtained from `64.1 kg CaC_(2) ` is

A

7kg

B

14kg

C

21kg

D

28kg

Text Solution

Verified by Experts

The correct Answer is:
D
64kg of `CaC_(2)` produces ethylene=28kg
Amount of polythene produced=28kg
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