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When CH(3)CH(2)CHCl(2) is treated with N...

When `CH_(3)CH_(2)CHCl_(2)` is treated with `NaNH_(2)` the product formed is

A

`CH_(3)CH-CH_(2)`

B

`CH_(3)-CH-=CH`

C

D

Text Solution

Verified by Experts

The correct Answer is:
B
`CH_(3)CH_(2)CHCl_(2)+2NaNH_(2) underset(196K)overset(Liq.NH_(3))to CH_(3)C-=CH+2NaCl+2NH_(3)`
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