Ethene is shaken with aqueous solution of `Br_(2)` and `NaCl_(2)`. Which of the following is not the possible product?

Options

A. `underset(CH_(2)Br)underset(|)(CH_(2))Br`
B. `underset(CH_(2)Cl)underset(|)(CH_(2))Br`
C. `underset(CH_(2)Cl)underset(|)(CH_(2))Cl`
D. `underset(CH_(2)OH)underset(|)(CH_(2))Br`

Explanation

To determine which product is not possible when ethene is reacted with an aqueous solution of Br₂ and NaCl₂, we can analyze the reactions step by step.

### Step 1: Understand the Reactants
Ethene (C₂H₄) is an alkene with a double bond between the two carbon atoms. When it reacts with Br₂, it undergoes an electrophilic addition reaction.

### Step 2: Reaction with Br₂
When ethene reacts with bromine (Br₂), the double bond opens up, leading to the formation of a bromonium ion intermediate. The reaction can be represented as follows:

1. The double bond in ethene attacks a bromine molecule, resulting in the formation of a cyclic bromonium ion.
2. The bromonium ion is then attacked by a bromide ion (Br⁻) from the bromine molecule, leading to the formation of 1,2-dibromoethane (C₂H₄Br₂).

**Possible Product from Br₂:**
- 1,2-Dibromoethane (C₂H₄Br₂)

### Step 3: Reaction with NaCl₂
Next, we consider the reaction with NaCl₂. In this case, the presence of NaCl₂ suggests that chloride ions (Cl⁻) can also participate in the reaction.

1. The bromonium ion can also be attacked by a chloride ion (Cl⁻) instead of a bromide ion (Br⁻).
2. This can lead to the formation of a product where one carbon has a bromine atom and the other has a chlorine atom, resulting in 1-bromo-2-chloroethane (C₂H₄BrCl).

**Possible Product from NaCl₂:**
- 1-Bromo-2-chloroethane (C₂H₄BrCl)

### Step 4: Aqueous Solution Consideration
Since the reaction is in an aqueous solution, water (H₂O) can also act as a nucleophile. The hydroxide ion (OH⁻) can replace one of the halides.

1. The bromonium ion can be attacked by water, leading to the formation of 1-bromoethanol (C₂H₄BrOH).

**Possible Product from Aqueous Solution:**
- 1-Bromoethanol (C₂H₄BrOH)

### Step 5: Identify the Impossible Product
Now, we need to identify which of the products listed in the options is not possible based on the reactions described above.

- **Possible Products:**
- 1,2-Dibromoethane (C₂H₄Br₂)
- 1-Bromo-2-chloroethane (C₂H₄BrCl)
- 1-Bromoethanol (C₂H₄BrOH)

If one of the options does not match any of the products formed through these reactions, that option is the correct answer.

### Conclusion
Based on the analysis, the product that is not possible from the reaction of ethene with an aqueous solution of Br₂ and NaCl₂ is the one that does not fit into the products formed from the reactions outlined above.

**Final Answer: The product that is not possible is option C.**