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The reduction of 1,3-pentadience with so...

The reduction of 1,3-pentadience with sodium in liquid ammonia in the persence of an alcohol gives

A

pentane

B

2-pentene

C

1-pentane

D

propene+ethene

Text Solution

Verified by Experts

The correct Answer is:
B
`Na//liq NH_(3)` is a reducing agent
`CH_(2)=CH-CH=CH-CH_(3) underset("alcohol")overset(Na//liq.NH_(3))to underset("Pent-2-ene")(CH_(3)-CH_(2)-CH-CH_(3))`
This is a brich reduction to reduce terminal double bond only.
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