Home
Class 12
CHEMISTRY
CH(3)CH(2)CH=CH(2) overset(NBs)to X over...

`CH_(3)CH_(2)CH=CH_(2) overset(NBs)to X overset(alc. KOH)to Y`.
The compound Y is

A

But-2-en-2-ol

B

But-3-en-1-ol

C

1,3-Butadience

D

1,2-Butadiene

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given problem step by step, we will analyze the reactions involving the compound CH₃CH₂CH=CH₂ (butene) with N-bromosuccinimide (NBS) and alcoholic KOH. ### Step 1: Reaction with NBS 1. **Identify the starting compound**: The starting compound is CH₃CH₂CH=CH₂, which is 1-butene. 2. **Understand the role of NBS**: N-bromosuccinimide (NBS) is used for allylic bromination. It will brominate the hydrogen atom at the allylic position (the carbon adjacent to the double bond). 3. **Identify the allylic position**: In 1-butene, the allylic position is the carbon atom next to the double bond. Therefore, the hydrogen on the second carbon (CH₂) will be replaced by a bromine atom. 4. **Write the product of the reaction**: The product after bromination will be CH₃CHBrCH=CH₂ (3-bromobutene). ### Step 2: Reaction with Alcoholic KOH 1. **Identify the product from Step 1**: The product from the first step is CH₃CHBrCH=CH₂. 2. **Understand the role of alcoholic KOH**: Alcoholic KOH is a strong base that promotes dehydrohalogenation, which means it will remove a hydrogen atom and a halogen atom (bromine in this case) to form a double bond. 3. **Identify the hydrogen and bromine to be removed**: In CH₃CHBrCH=CH₂, we can remove the hydrogen from the carbon adjacent to the bromine (the second carbon) and the bromine itself. 4. **Write the product of the reaction**: After removing H and Br, we will form a new double bond between the second and third carbons, resulting in CH₂=CH-CH=CH₂, which is 1,3-butadiene. ### Final Answer The compound Y is **1,3-butadiene**. ---
To solve the given problem step by step, we will analyze the reactions involving the compound CH₃CH₂CH=CH₂ (butene) with N-bromosuccinimide (NBS) and alcoholic KOH. ### Step 1: Reaction with NBS 1. **Identify the starting compound**: The starting compound is CH₃CH₂CH=CH₂, which is 1-butene. 2. **Understand the role of NBS**: N-bromosuccinimide (NBS) is used for allylic bromination. It will brominate the hydrogen atom at the allylic position (the carbon adjacent to the double bond). 3. **Identify the allylic position**: In 1-butene, the allylic position is the carbon atom next to the double bond. Therefore, the hydrogen on the second carbon (CH₂) will be replaced by a bromine atom. 4. **Write the product of the reaction**: The product after bromination will be CH₃CHBrCH=CH₂ (3-bromobutene). ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • HALOALKANES AND HALOARENES

    DINESH PUBLICATION|Exercise Brain storming multiple choice questions|11 Videos

  • IONIC EQUILIBRIUM

    DINESH PUBLICATION|Exercise UNIT TEST -2|30 Videos

Similar Questions

Explore conceptually related problems

Complete the following by providing (A),(B),(C) and (D) : (i) CH_(3)CH_(2)CH_(2) OH overset(PBr)(to) (A) overset(alc.KOH)underset(Delta)(to) (B) overset(HBr)(to)(C) overset(NH_(3))(to) (D) (ii) CH_(3)CH_(2)CH_(2)I overset(alc.KOH)underset(Delta)(to)(A)overset(H^(+)//H_(2)O)(to) (B)overset(SOCI_(2))(to)(C) overset(H)underset(LiAIH_(4))(to) (D) (iii) CH_(3)CHBrCH_(3) overset(alc.KOH)underset(Delta)(to) (A) overset(HBr)underset("Peroxide")(to) (B) overset(Nal)underset("Acetone")(to) (C) overset(H)underset("Ether")(to) (iv) CH_(3)CH_(2)CH=CH_(2) overset(NBS)underset("Light")(to) (A) overset(alc. KOH)underset(Delta)(to)(B) overset(HBr)(to)(C) (v) CH_(3)CH_(2)MgBroverset(CH_(3)CHO //H_(2)O)(to) (A) overset(HBr)(to)(B) overset(alc.KOH)underset(Delta)(to)(C) (A) overset(NH_(3))(to) (B) overset(CHCI_(3)+KOH(alc.))(to)(C) overset(Na)underset(C_(2)H_(5)OH)(to) CH_(3)-underset(CH_(3))underset(|)CH-NHCH_(3) (viii) CH_(3)CH_(2)Br overset((i)(CH_(2))_(6)N_(4))underset((ii)H_(2)O //H^(+))(to) (A) overset(NaOH)(to)(B) overset((i)O_(3))underset((ii)Zn//HOH)(to)(A) +(C) overset(conc.NaOH)(to)(D)

CH_(3)CH_(2)CHCI_(2) overset(Aq.KOH)rarr ?

Knowledge Check

  • CH_2=CHCH_2CH=CH_2overset(NBS)toA , A is

    A
    `CH_2=CH underset(Br)underset|CHCH=CH_2`
    B
    `CH_2=CHCH=CHCH_2Br`
    C
    `CH_2=CHCH_2CH=CHBr`
    D
    `CH_2=CHCH_2underset(Br)underset|C=CH_2`

  • Consider the reaction CH_(3)CH_(2)CH_(2)OH overset(PCl_(5))toAunderset(KOH)overset(alc)toB . The compound 'B' is

    A
    propane
    B
    propene
    C
    propyne
    D
    propanal

  • CH_3CH_2CH_2OH overset(PCl_5)toX overset(alc. KOH)to Y , where Y is _________.

    A
    propane
    B
    propanol
    C
    propene
    D
    propyne

    • Similar Questions

    Explore conceptually related problems

    Complete the following reactions: CH_(3)CH_(2)CH_(2)OH overset(SOCl_(2)) to? overset(alc. KOH) to? overset(HBr) to ? overset(aq. KOH) to

    CH_(3)CH_(2)COOH overset(Cl_(2)//Fe)rarr X overset(KOH(alc))rarrY compound Y is

    CH_(3)-CH_(2)-COOHunderset("Red P")overset(Cl_(2))to A overset(alc. KOH) to B The product B is ________.

    CH_(2)= CHCH_(2)CH=CH_(2) overset(NBS)rarr X( Major ),(X) is :

    The compound B formed in the following sequence of reaction CH_(3)CH_(2)CH_(2)OH overset(PCl_(5))rarrA overset(alc.KOH)rarrB is

    Home
    Profile