When sodium salt of ethanol is treated with ethyl bromide, the product formed is :

Options

A. Methoxyethane
B. Ethoxyethanol
C. Methyl ethyl ketone
D. Diethylether

Explanation

To solve the question "When sodium salt of ethanol is treated with ethyl bromide, the product formed is:", we can follow these steps:

### Step 1: Identify the Reactants
The sodium salt of ethanol can be represented as:
\[ \text{C}_2\text{H}_5\text{ONa} \]
This is formed by replacing the hydrogen atom of the hydroxyl group (-OH) in ethanol (C2H5OH) with sodium (Na).

The other reactant is ethyl bromide, represented as:
\[ \text{C}_2\text{H}_5\text{Br} \]

### Step 2: Understand the Reaction
When the sodium salt of ethanol reacts with ethyl bromide, a nucleophilic substitution reaction occurs. The sodium salt acts as a nucleophile due to the presence of the negatively charged alkoxide ion (C2H5O^-).

### Step 3: Write the Reaction
The reaction can be summarized as follows:
\[ \text{C}_2\text{H}_5\text{ONa} + \text{C}_2\text{H}_5\text{Br} \rightarrow \text{C}_2\text{H}_5\text{O}\text{C}_2\text{H}_5 + \text{NaBr} \]

### Step 4: Identify the Product
The product formed from this reaction is diethyl ether, which can be represented as:
\[ \text{C}_2\text{H}_5\text{O}\text{C}_2\text{H}_5 \]
This compound is commonly known as diethyl ether or ethoxyethane.

### Step 5: Conclusion
Thus, the product formed when sodium salt of ethanol is treated with ethyl bromide is diethyl ether.

### Final Answer
The product formed is diethyl ether (C2H5OC2H5).

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