`CH_(3)-CH=CH_(2)+HI rarr X`. Here X is

Options

A. `CH_(3)CH_(2)CH_(2)I`
B. `CH_(3)CHICH_(3)`
C. `CH_(3)CH_(2)CH_(3)`
D. `CH_(3)CH_(3)+CH_(4)`

Explanation

To solve the reaction \( CH_3-CH=CH_2 + HI \rightarrow X \), we will follow these steps:

### Step 1: Identify the Reactants
The reactant is an alkene, specifically propene (\( CH_3-CH=CH_2 \)), and it is reacting with hydrogen iodide (HI).

**Hint:** Look for the functional groups in the reactants to understand the type of reaction.

### Step 2: Understand the Reaction Type
The reaction between an alkene and HI is an example of a nucleophilic addition reaction. In this case, HI will add across the double bond of the alkene.

**Hint:** Recall that alkenes undergo addition reactions where the double bond is broken.

### Step 3: Apply Markovnikov's Rule
According to Markovnikov's rule, when HX (where X is a halogen) adds to an alkene, the hydrogen atom (H) will attach to the carbon with the greater number of hydrogen atoms already attached, while the halogen (I) will attach to the carbon with fewer hydrogen atoms.

**Hint:** Identify the carbon atoms in the double bond and count the hydrogen atoms attached to each.

### Step 4: Analyze the Double Bond
In propene (\( CH_3-CH=CH_2 \)):
- The first carbon (C1) has 3 hydrogen atoms.
- The second carbon (C2) has 1 hydrogen atom.

According to Markovnikov's rule:
- The iodine (I) will attach to C2 (the carbon with fewer hydrogens).
- The hydrogen (H) will attach to C1 (the carbon with more hydrogens).

**Hint:** Determine which carbon will receive the halogen and which will receive the hydrogen based on the number of hydrogens.

### Step 5: Write the Product Structure
After applying Markovnikov's rule:
- C1 will have an additional hydrogen, making it \( CH_3-CH \).
- C2 will have the iodine attached, making it \( CHI \).

The product will be:
\[ CH_3-CH(I)-CH_3 \]

### Step 6: Finalize the Product
The final product can be written as:
\[ CH_3-CH(I)-CH_3 \]
This compound is 2-iodopropane.

**Hint:** Ensure that the final product is correctly represented with the appropriate functional groups.

### Conclusion
The product \( X \) formed from the reaction \( CH_3-CH=CH_2 + HI \) is \( CH_3-CH(I)-CH_3 \) or 2-iodopropane.