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Arrange the following halides in the dec...

Arrange the following halides in the decreasing order of `S_(N^(1))` reactivity : `underset((I))(CH_(3)CH_(2)CH_(2)Cl), underset((II)) (CH_(2)=CHCH(Cl)CH_(3)), underset((III))(CH_(3)CH_(2)CH(Cl)CH_(3))`

A

I gt II gt III

B

II gt I gt III

C

II gt III gt I

D

III gt II gt I

Text Solution

Verified by Experts

The correct Answer is:
C
Reactivity decreases in order : Allylic `gt 2^(@)gt 1^(@)` aliphatic halides.
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Arrange the following halides in the decreasing order of S_N1 reactivity: CH_3underset((I))CH_2CH_2Cl CH_2=CHunderset((II))CH(Cl)CH_3 , CH_3CH_2underset(III)CH(Cl)CH_3

Arrange the following in order of decreasing tendency towards S_(N^(2)) reaction : {:(underset("(I)")(CH_(3)CH_(2)CH_(2)CH_(2)Cl)", "underset("(II)")(CH_(3)CH_(2)CHClCH_(3)",")),(underset("(III)")((CH_(3))_(2)CHCH_(2)Cl)", "underset("(IV)")((CH_(3))_(3)C-Cl)):}

Arrange the following halides in the decreasing order of SN^1 reactivity : (I) CH_3CH_2CH_2Cl, (II) CH_2=CHCH(Cl)CH_3 (III) CH_3CH_2CH(Cl)CH_3

Arrange the following halides in order increasing S_(N^(2)) reactivity CH_(3)Cl,CH_(3)Br,CH_(3)CH_(2)Cl,(CH_(3))_(2)CHCl .

Arrange the following alkenes in the decreasing order of stability: (I) underset(CH_(3)C=CHCH_(3))underset(|)(CH_(3)) (II) underset(CH_(3)CHCH=CH_(2))underset(|)(CH_(3)) (III) underset(CH_(2)=CHCH_(2)CH_(3))underset(|)(CH_(3))

Arrange the following compounds in increasing order of S_(N^(1)) reactivity. (a). (I). ClCH_(2)CH=CHCH_(2)CH_(3) , (II). CH_(3)C(Cl)=CHCH_(2)CH_(3) , (III). CH_(3)CH=CHCH_(2)CH_(2)Cl (b). (I). CH_(3)CH_(2)Br , (II). CH_(2)=CHCH(Br)CH_(3) , (III). CH_(2)=CHBr, (IV). CH_(3)CH(Br)CH_(3) (c). (I). (CH_(3))_(3)CBr , (II). (CH_(3))_(2)CHBr , (III). CH_(3)CH_(2)CH_(2)Br ,

The increasing order of the reactivity of the following halides for the S_(N) 1 reaction is underset((I))underset(Cl)underset(|)(CH_(3))CHCH_(2)CH_(3) " " underset((II))(CH_(3)CH_(2)CH_(2)Cl) " " underset((III))(p-H_(3)CO-C_(6)H_(4)-CH_(2)Cl

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