The reaction of propene with HOCl proceeds via the addition of :

Options

A. `H^(+)` in the first step
B. `Cl^(+)` in the first step
C. `OH^(-)` in the first step
D. `Cl^(+)` and `OH^(-)` in a single step

Answer

B

Explanation

In the addition of `H-overset(delta)(O)-overset(delta+)(Cl)` to propene, the first step involves the addition of `Cl^(+)`.
`HO-Cl hArr HO^(-)+Cl^(+)`
`underset("Propene")(CH_(3)-CH=CH_(2)overset(Cl^(+))rarr CH_(3)-overset(+)(C )H-CH_(2)Cl overset(OH^(-))rarr CH_(3)-overset(OH)overset(|)(C )H-CH_(2)Cl` .