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H(3)C-underset(CH(3))underset(|)(CH)-CH=...

`H_(3)C-underset(CH_(3))underset(|)(CH)-CH=CH_(2)+HBr to A`.
A is predominantly

A

`CH_(3)-underset(Br)underset(|)(C )H-underset(CH_(3))underset("| ")("C ")H-CH_(3)`

B

`CH_(3)-underset(CH_(3))underset("| ")("C ")H-underset(Br)underset(|)(C )H-CH_(3)`

C

`CH_(3)-underset(CH_(3))underset("| ")("C ")H-CH_(2)Br`

D

`CH_(3)-overset("Br ")overset("| ")underset(CH_(3))underset("| ")("C ")-CH_(2)CH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
D

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