Dehalogenation of vicinal dihalides with Zn/alc. Mainly produces

Options

A. Alcohol
B. Alkene
C. Alkyne
D. Alkane

Explanation

To solve the question regarding the dehalogenation of vicinal dihalides with zinc in an alcoholic medium, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Vicinal Dihalides**:
- Vicinal dihalides are compounds where two halogen atoms are attached to adjacent carbon atoms. For example, consider 1,2-dibromoethane (CH2Br-CHBr2).

2. **Reaction Conditions**:
- The reaction involves zinc (Zn) in the presence of an alcoholic medium. Zinc acts as a reducing agent that facilitates the removal of halogen atoms.

3. **Dehalogenation Process**:
- In this reaction, both halogen atoms (in this case, bromine) will be removed from the vicinal dihalide. The process is called dehalogenation.

4. **Formation of Alkene**:
- When the two bromine atoms are removed, a double bond is formed between the two carbon atoms. For 1,2-dibromoethane, the removal of Br atoms results in the formation of ethene (CH2=CH2).

5. **Byproduct Formation**:
- Along with the alkene, zinc bromide (ZnBr2) is formed as a byproduct due to the reaction of zinc with the halogen atoms.

6. **Final Product**:
- Therefore, the main product of the reaction is ethene (CH2=CH2), which is an alkene.

### Conclusion:
The dehalogenation of vicinal dihalides with Zn in an alcoholic medium mainly produces an alkene.