Product C in the reaction,
`C_(2)H_(5)Broverset(NaOH)underset(("aqueous"))toAoverset(Na)toBoverset(CH_(3)I)toC` will be

Options

A. Propane
B. Ethyl iodide
C. Ethane
D. Ethyl methyl ether

Explanation

To determine the product C in the given reaction sequence, we will follow the steps outlined in the video transcript.

### Step-by-Step Solution:

1. **Identify the starting compound**: The starting compound is C₂H₅Br, which is ethyl bromide.

2. **First Reaction with Aqueous NaOH**:
- Ethyl bromide (C₂H₅Br) reacts with aqueous NaOH.
- This reaction typically leads to the formation of an alcohol through a nucleophilic substitution reaction.
- The bromine atom is replaced by a hydroxyl group (OH), resulting in the formation of ethyl alcohol (C₂H₅OH).
- **Product A**: C₂H₅OH (ethyl alcohol).

3. **Second Reaction with Sodium (Na)**:
- The ethyl alcohol (C₂H₅OH) then reacts with sodium (Na).
- In this reaction, sodium reacts with the alcohol to form an alkoxide.
- The reaction can be represented as:
\[ \text{C}_2\text{H}_5\text{OH} + \text{Na} \rightarrow \text{C}_2\text{H}_5\text{O}^-\text{Na}^+ + \frac{1}{2} \text{H}_2 \]
- **Product B**: C₂H₅ONa (sodium ethoxide).

4. **Third Reaction with Methyl Iodide (CH₃I)**:
- The sodium ethoxide (C₂H₅ONa) now reacts with methyl iodide (CH₃I).
- This is another nucleophilic substitution reaction where the ethoxide ion acts as a nucleophile and attacks the methyl group, leading to the formation of an ether.
- The product formed is ethyl methyl ether (C₂H₅OCH₃).
- **Product C**: C₂H₅OCH₃ (ethyl methyl ether).

### Final Answer:
The product C in the reaction sequence is **ethyl methyl ether (C₂H₅OCH₃)**.

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