An organic compound of molecular formula `C_4H_10O` does not react with sodium. With excess of HI, it gives only one type of alkyl halide. The compound is

Options

A. Ethoxy ethane
B. 2- Methoxy propane
C. 1-Methoxy propane
D. 1-Butanol.

Explanation

To solve the problem, we need to identify the organic compound with the molecular formula C4H10O that does not react with sodium and produces only one type of alkyl halide when treated with excess HI.

### Step-by-Step Solution:

1. **Analyze the Molecular Formula:**
The molecular formula given is C4H10O. This indicates that the compound contains 4 carbon atoms, 10 hydrogen atoms, and 1 oxygen atom.

2. **Determine the Functional Group:**
The compound does not react with sodium, which suggests that it is not an alcohol (as alcohols typically react with sodium to release hydrogen gas). Therefore, the oxygen is likely part of an ether or an ester.

3. **Consider the Reaction with HI:**
When the compound is treated with excess HI, it produces only one type of alkyl halide. This implies that the compound must have a symmetrical structure, allowing for only one type of alkyl group to be formed upon substitution.

4. **Identify Possible Structures:**
Given that the compound is likely an ether (since it does not react with sodium), we can consider the structure of ethers. The simplest ether that fits the molecular formula C4H10O is diethyl ether (C2H5-O-C2H5).

5. **Check the Reaction with HI:**
When diethyl ether (C2H5-O-C2H5) reacts with excess HI, it can be cleaved to produce two molecules of ethyl iodide (C2H5I). Since both alkyl groups are the same (C2H5), this results in only one type of alkyl halide being produced.

6. **Conclusion:**
Therefore, the organic compound with the molecular formula C4H10O that does not react with sodium and gives only one type of alkyl halide upon reaction with excess HI is diethyl ether (C2H5-O-C2H5).

### Final Answer:
The compound is diethyl ether (C2H5-O-C2H5).