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An alkene, C(7)H(14) on reductive ozonol...

An alkene, `C_(7)H_(14)` on reductive ozonolysis gave propanal and a ketone. The probable ketone is

A

Acetone

B

Ethyl methyl ketone

C

2-Pentanone

D

3-Pentanone.

Text Solution

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The correct Answer is:
To solve the problem, we need to identify the ketone that is produced alongside propanal when the alkene with the formula \( C_7H_{14} \) undergoes reductive ozonolysis. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Structure of the Alkene The alkene has the molecular formula \( C_7H_{14} \). This indicates that it has a chain of 7 carbon atoms. **Hint:** Remember that alkenes have at least one double bond, which affects how they react during ozonolysis. ### Step 2: Identify the Products of Reductive Ozonolysis During reductive ozonolysis, the alkene will break at the double bond and form an aldehyde and a ketone. We know that one of the products is propanal (an aldehyde). **Hint:** Aldehydes have the functional group -CHO, which is important for identifying the structure. ### Step 3: Determine the Structure of Propanal Propanal has three carbon atoms and can be represented as: \[ \text{CH}_3\text{CH}_2\text{CHO} \] This indicates that the double bond in the original alkene must have been located such that breaking it results in propanal. **Hint:** The position of the double bond in the alkene is crucial for determining the products of ozonolysis. ### Step 4: Identify the Ketone Since propanal has three carbon atoms, the remaining four carbon atoms from the original alkene must form a ketone. A ketone has the general structure \( R_2C=O \). **Hint:** The ketone must have four carbon atoms, so consider possible structures that fit this requirement. ### Step 5: Evaluate Possible Ketones We need to find a ketone with four carbon atoms. The options typically include: 1. Acetone (3 carbon atoms) 2. Ethyl methyl ketone (4 carbon atoms) 3. 2-Pentanone (5 carbon atoms) 4. 3-Pentanone (5 carbon atoms) From these options: - Acetone is not valid since it has only 3 carbon atoms. - Ethyl methyl ketone (also known as 3-pentanone) has 4 carbon atoms, which fits our requirement. - 2-Pentanone and 3-Pentanone both have 5 carbon atoms, which do not fit. **Hint:** Ensure that the ketone you choose has the correct number of carbon atoms as derived from the ozonolysis products. ### Conclusion The probable ketone formed alongside propanal from the ozonolysis of the alkene \( C_7H_{14} \) is **ethyl methyl ketone**. **Final Answer:** Ethyl methyl ketone (also known as 3-pentanone).

To solve the problem, we need to identify the ketone that is produced alongside propanal when the alkene with the formula \( C_7H_{14} \) undergoes reductive ozonolysis. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Structure of the Alkene The alkene has the molecular formula \( C_7H_{14} \). This indicates that it has a chain of 7 carbon atoms. **Hint:** Remember that alkenes have at least one double bond, which affects how they react during ozonolysis. ### Step 2: Identify the Products of Reductive Ozonolysis ...
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