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C(3)H(8)Ooverset(O)underset(K(2)Cr(2)"O"...

`C_(3)H_(8)Ooverset(O)underset(K_(2)Cr_(2)"O"//H)rarrC_(3)H_(6)Ooverset(I_(2))underset(NaOH)rarrCHI_(3)`
The starting compound is

A

1-Propanol

B

Propanal

C

2-propanol

D

Ethyl methyl ether.

Text Solution

Verified by Experts

The correct Answer is:
C

`C_(3)H_(8)O` is an alcohol and `C_(3)H_(6)O` is a ketone which responds to iodoform test. The reaction is
`CH_(3)overset("OH")overset("| ")("CH")-CH_(3)overset([O])rarrCH_(3)-overset(O)overset(||)C-CH_(3)overset(I_(2)//NaOH)rarrCHI_(3)+CH_(3)COONa`
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