When vapours of isopropyl alcohol are passed over heated copper, the major product obtained is

Options

A. Propane
B. Propylene
C. Acetaldehyde
D. Acetone.

Explanation

To solve the question regarding the major product obtained when vapours of isopropyl alcohol are passed over heated copper, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactant**:
The reactant in this case is isopropyl alcohol, which has the molecular formula \( \text{C}_3\text{H}_8\text{O} \) and can be represented structurally as:
\[ \text{CH}_3\text{C(OH)}\text{CH}_3 \]

2. **Determine the Type of Alcohol**:
Isopropyl alcohol (2-propanol) is a secondary alcohol because the carbon atom bearing the hydroxyl group (OH) is attached to two other carbon atoms.

3. **Understand the Reaction Conditions**:
The reaction involves passing the vapours of isopropyl alcohol over heated copper at around 573 K. Copper acts as an oxidizing agent under these conditions.

4. **Predict the Product of Oxidation**:
- Secondary alcohols oxidize to form ketones.
- Therefore, the oxidation of isopropyl alcohol will yield a ketone.

5. **Identify the Specific Ketone Formed**:
The oxidation of isopropyl alcohol results in the formation of acetone, which has the structural formula:
\[ \text{CH}_3\text{C(=O)}\text{CH}_3 \]
This compound is also known as propanone.

6. **Conclusion**:
The major product obtained from the oxidation of isopropyl alcohol when passed over heated copper is acetone, or propanone.

### Final Answer:
The major product obtained is **propanone (acetone)**.