A substance `C_(4)H_(10)O` yields on oxidation a compound `C_(4)H_(8)O` which gives an oxime and a positive iodoform test. The original substance on treatment with conc. `H_(2)SO_(4)` gives `C_(4)H_(8)`, The structure of the compound is

Options

A. `CH_(3)CH_(2)CH_(2)OH`
B. `CH_(3)CH(OH)CH_(2)CH_(3)`
C. `(CH_(3))COCH`
D. `CH_(3)CH_(2)-OCH_(2)CH_(3)`

Answer

B

Explanation

`underset(C_(4)H_(10)O)(CH_(3)CH(OH)CH_(2)CH_(3))overset("conc." H_(2)SO_(4))rarrunderset(C_(4)H_(8))(CH_(3)CH=CHCH_(3))`
`underset("2-Butanol")(CH_(3)CHOOHCH_(2)CH_(3))overset([O])rarrunderset("Butanone")(CH_(3)COCH_(2)CH_(3))`
Butanone gives botha an oxime and postivie iodoform test, therefore, the original compound is 2-butanol.