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One mole of symmetrical alkene upon ozon...

One mole of symmetrical alkene upon ozonolysis gives two moles of an aldehyde having the molecular mass `44 u`. Predict the alkene.

A

ethene

B

propene

C

1-butene

D

2-butene.

Text Solution

Verified by Experts

The correct Answer is:
D
`C_(n)H_(2n)O=44rArrC_(n)H_(2n)=44-16=28`
`therefore` n = 2
Hence `CH_(3)-CH=CH-CH_(3)` is a symmetrical
`therefore underset("2-Butene")(CH_(3)-CH=CH-CH_(3))overset((i)O_(3))underset((ii)Zn//H_(2)O)rarrunderset("Acetaldehyde")(2CH_(3)-CH=O)`
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