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In the following reaction sequence, prod...

In the following reaction sequence, products I, J, and L are formed. `K` represents a reagent.

The structures of product `I` is :


The structures of compounds `J` and `K`, respectively, are :

The structure of product `L` is :

A

B

C

D

Text Solution

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The correct Answer is:
D
`NaBH_(4)` reduces CHO selectively into `CH_(2)OH`, which is further converted into corresponding bromide by `PBr_(3)` without affecting the triple bond.
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