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When SnCl(2) is treated with HgCl(2), th...

When `SnCl_(2)` is treated with `HgCl_(2)`, the products formed are

A

`Sn+HgCl_(4)`

B

`Sn+Cl_(2)+Hg_(2)Cl_(2)`

C

`SnCl_(4)` and `Hg_(2)Cl_(2)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
`SnCl_(2)` is reducing agent and reduces `Hg^(2+)` to `Hg_(2)^(2+)` and itself oxidised to `Sn^(4+)`.
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