An alkyl halide reacts with a group 14 element, 'Y' at 570 K with Cu as a catalyst producing a dialkyl chloro compound 'Z'. The compound 'Z' on hydrolysis gives another compound which is a strong water repellent and quite inert chemically. The dioxide of 'Y' is acidic in nature. The alkyl halide can also be obtained from methan after mono-substitution. The comp 'Y' and 'Z' are

Options

A. `C,C_(2)H_(4)Cl_(2)`
B. `Sn,(CH_(3))_(2)SnCl_(2)`
C. `Si,(C_(2)H_(5))_(2)SiCl_(2)`
D. `Si,(CH_(3))_(2)SiCl_(2)`

Answer

D

Explanation

Since the alkyl halide is obtained from `CH_(4)` after monosubstitution it must be `CH_(3)Cl` or `CH_(3)Br` or `CH_(3)I` or `CH_(3)F`. However, this alkyl halide reacts compound. Hence alkyl halid is `CH_(3)Cl`. Also Y can be either C or Si since it gives an acidic dioxide. But the hydrolysis of Z (produced from Y) gives a water repellant and chemically inert compound. it must be a polymeric compound, that too of Si, i.e., silicone. carbon cannot give such a polymeric compound. hence Y is si. the reaction involved by
`2CH_(3)Cl+underset("(Y)")(Si) overset(Cu.570K)tounderset("(Z)")((CH_(3))_(2)SiCl_(2))`
`(CH_(3))_(2)SiCl_(2) overset(+H_(2)O)underset(-HCl)to -O-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(Si)-O-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(Si)-O-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(Si)-O-`