Home
Class 12
CHEMISTRY
CO forms a volatile compound with...

CO forms a volatile compound with

A

Ni

B

Cu

C

Al

D

Si

Text Solution

Verified by Experts

The correct Answer is:
A
`Ni+4CO to Ni(CO)_(4)`.
Promotional Banner

Topper's Solved these Questions

  • THE CARBON FAMILY

    DINESH PUBLICATION|Exercise RQ|102 Videos

  • THE CARBON FAMILY

    DINESH PUBLICATION|Exercise Selected straight|31 Videos

  • SURFACE CHEMISTRY

    DINESH PUBLICATION|Exercise BRAIN STORMING MULTIPLE CHOICE QUESTIONS (MCQs)|8 Videos

  • THE HALOGEN FAMILY

    DINESH PUBLICATION|Exercise ULTIMATE PREPARATORY PACKAGE|16 Videos

Similar Questions

Explore conceptually related problems

Which of the follwing are main requirements for vapour phase refining ? (i) Metal should form a volatile compound with the reagent (ii) The volatile compound should be easily decompsoable to give back pure metal (iii)Metal should be very reactive and form a stable compound with the reagent

Most volatile compound is

One of the following metals forms a volatile compound and this property is taken advantages for its extraction. This metal is

At high temperature, carbon reacts with water to produce a mixture of CO and H_(2) . C + H_(2) O overset ("Heat heat")rarr CO + H_(2) CO is separated from H_(2) and then used to separate Ni from CO by forming a volatile compound, nickel tetracarbonyl (Ni(CO)_(4)) . Ni + 4CO rarr Ni(CO)_(4) (a) Formation of volatile Ni(CO)_(4) and its subsequent heating give pure Ni . Name the process involved. (b) How many moles of Ni(CO)_(4) could be obtained from CO produced by the reaction of 75.0 g is carbon ?

the most volatile compound is

At high temperature carbon reacts with water to prodcue a mixture of carbon monoxide, CO and hydrogen, H_(2) . C+H_(2)O overset("red heat")to CO+H_(2) CO is separted from H_(2) and then used to separtee nickel from cobalt by forming a volatile compound, nickel tetracarbonyl, Ni(CO__(3)) Ni+4CO to Ni(CO)_(4) Formation of volatile Ni(CO)_(4) and its subsquent heating give Ni. Process is called: