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PbCl(4) exists but PbBr(4) and PbI(4) do...

`PbCl_(4)` exists but `PbBr_(4)` and `PbI_(4)` do not because of

A

Inability of bromine and iodine of oxidise `Pb^(2+)` to `Pb^(4+)`

B

`Br^(-)` and `I^(-)` ions are bigger in size

C

more electropositive nature of bromine and iodine

D

Chlorine is a gas

Text Solution

Verified by Experts

The correct Answer is:
A
`Br_(2)` and `I_(2)` are weak oxidising agent and as such cannot oxidise `Pb^(2+)` to `Pb^(4+)`
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