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When SO2 is passed through acidified K2C...

When `SO_2` is passed through acidified `K_2Cr_2O_7` solution

A

The solution turns blue

B

The solution is decolourised

C

`SO_2` is reduced

D

Green `Cr_2(SO_4)_3` is formed

Text Solution

Verified by Experts

The correct Answer is:
D
`({:(K_2Cr_2O_7+4H_2SO_4to,K_2SO_4+Cr_2(SO_4)_3+4H_2O+3O),(SO_2+H_2O+Oto,H_2SO_4"]" xx3):})/(ul(K_2Cr_2O_7+H_2SO_4+3SO_2toK_2SO_4+Cr_2(SO_4)_3+H_2O))`
Due to the formation of `Cr^(3+)` ions or `Cr_2(SO_4)_3`, the solution turns green .
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