The oxidation states of sulphur in the anions `SO_(3)^(2-), S_(2)O_(4)^(2-)`, and `S_(2)O_(6)^(2-)` follow the order

Options

A. `S_2O_6^2 lt S_2O_4^2 lt SO_3^2`
B. `S_2O_4^2 lt SO_3^2 lt S_2O_6^2`
C. `SO_3^2 lt S_2O_3^2 lt S_3O_6^2`
D. `S_2O_4^2 lt S_2O_6^2 lt SO_3^2`

Answer

B

Explanation

O.S. of S in `SO_3^(2-)= +4`
O.S. of S in `S_2O_4^(2-)= +3`
O.S. of S in `S_2O_6^(2-)= +5`
(None of these contains peroxide linkage. )
The correct order of increasing O.S. is ,
`S_2O_4^(2-) lt SO_3^(2-) lt S_2O_6^(2-)`